b) 5a=8b=3c => a/(1/5) =b/(1/8) =c/(1/3) 
=> a/(1/5) =2b/(1/4) =c/(1/3) = (a-2b+c)/ (1/5 -1/4 +1/3)=34/(17/60)=120 
a/(1/5) =120 =>a=120x1/5=24 
2b/(1/4) =120 hay 8.b=120 =>b=120:8=15 
c/(1/3) =120 =>c=120x1/3=40

mấy câu còn lại dễ nhưng mk ko thích làm

\(\frac{a}{5}=\frac{b}{8}=\frac{c}{3}\)và a - 2b + c = 34

Ta có:

\(\frac{a}{5}=\frac{b}{8}=\frac{c}{3}=\frac{a}{5}=\frac{2b}{16}=\frac{c}{3}\)

Áp dụng tính chất dãy tỉ số bằng nhau,, ta có:

\(\frac{a}{5}=\frac{2b}{16}=\frac{c}{3}=\frac{a-2b+c}{5-16+3}=\frac{34}{-8}=-\frac{17}{4}\)

\(\Rightarrow\frac{a}{5}=-\frac{17}{4}\Rightarrow a=-\frac{17}{4}.5=-\frac{85}{4}\)

\(\Rightarrow\frac{2b}{16}=-\frac{17}{4}\Rightarrow2b=-\frac{17}{4}.16=-68\Rightarrow b=68:2=34\)

\(\Rightarrow\frac{c}{3}=-\frac{17}{4}\Rightarrow c=-\frac{17}{4}.3=-\frac{51}{4}\)

Vậy a = .......

b = ...........

c = .............

\(\frac{a}{5}=\frac{b}{8}=\frac{c}{3}=\frac{a-2b+c}{5-2.8+3}=\frac{34}{-8}\)

=>a=\(\frac{34}{-8}.5=\frac{170}{-8}\)

b=\(\frac{34}{-8}.8=\frac{272}{-8}\)

c=\(\frac{34}{-8}.3=\frac{102}{-8}\)

1 k nhá

\(15a=10b=6c\Rightarrow\frac{a}{2}=\frac{b}{3}=\frac{c}{5}\)

Ta có:

 Đặt:

\(\frac{a}{2}=\frac{b}{3}=\frac{c}{5}=k\)

\(\Rightarrow a=k.2\)

\(\Rightarrow b=k.3\)

\(\Rightarrow c=k.5\)

Thế vào a .b . c = -1920, ta có:

\(\Rightarrow\left(k.2\right).\left(k.3\right).\left(k.5\right)=-1920\)

\(\Rightarrow k^3.30=-1920\)

\(\Rightarrow k^3=\left(-1920\right):30\)

\(\Rightarrow k^3=-64\)

\(\Rightarrow k=-4\)

Tự thê vào tìm a , b , c nah bạn ~

Ta thất:15a=10b=6c

\(\Rightarrow\frac{a}{10}=\frac{b}{15},\frac{b}{6}=\frac{c}{10}\)

\(\Rightarrow\frac{a}{20}=\frac{b}{30}\),\(\frac{b}{30}=\frac{c}{50}\)

Đặt a=29k,b=30k,c=50k

Mà abc=-1920\(\Leftrightarrow k^3=\frac{-8}{125}\)

\(\Leftrightarrow k=\frac{-2}{5}\)

\(\Leftrightarrow\hept{\begin{cases}a=20k=-8\\b=30k=-12\\c=50k=-20\end{cases}}\)

ta có: 15a=10ob=6c

Suy ra a/10=b/15 ; b/6=c/10

Suy ra a/20=b/30 ;b/30=c/50 suy ra a/20=b/30=c/50

Đặt: a/20=b/30=c/50=k

Suy ra a=20k;=30k;c=50k

Mà a,b,c=-1920

20k.30k.50k=-1920

k^3=-8/125 suy ra k=-2/5

suy ra a=20k=-8, b=30k=-12, c=50k=-20

Ta có: \(15a=10b=6c\)

\(\Rightarrow\left(15a\right)^3=15a.10b.6c\)

\(\Rightarrow3375a^3=\left(15.10.6\right).\left(a.b.c\right)\)

\(\Rightarrow3375a^3=900.\left(-1920\right)\)

\(\Rightarrow3375a^3=-1728000\)

\(\Rightarrow a^3=\frac{-1728000}{3375}=-512\)

\(\Rightarrow a=-8\)

Ta lại có: \(\hept{\begin{cases}10b=15a\\6c=15a\end{cases}\Rightarrow\hept{\begin{cases}10b=-120\\6c=-120\end{cases}\Rightarrow}\hept{\begin{cases}b=-12\\c=-20\end{cases}}}\)

Vậy \(a=-8;b=-12\text{ và }c=-20\)

\(\frac{a+3-3}{5-3}=\frac{b-2+2}{3+2}=\frac{c-1+1}{7+1}=\frac{a}{2}=\frac{b}{5}=\frac{c}{8}=\frac{3a}{6}=\frac{5b}{25}=\frac{7c}{56}=\frac{86}{37}\)

\(\Rightarrow\frac{a}{2}=\frac{86}{37}\Rightarrow a=\frac{172}{37};\frac{b}{5}=\frac{86}{37}\Rightarrow\frac{430}{37};\frac{c}{8}=\frac{86}{37}\Rightarrow\frac{688}{37}\)